A constant retarding force of 50 N is applied to a body of
mass 10 kg moving initially with a speed of 10 ms. The
body comes to rest after
(a) 2s
(b) 4 s
(C) 65
(d) 8s
Answers
Answered by
1
Answer:
answer in attachment
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Answered by
1
Answer:
2s
Explanation:
look it is simple as we know F=MA
and F is 50N and M is 10Kg therefore
A=F÷M
a=50÷10
a=5 m/s
and as retarding it is -5 m/s
therefore every second the speed reduce by 5
and so it takes two second to be 0
HIT 5 STAR
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