Question

A constant torque is acting on a wheels.If
Starting from rest,
the wheel makes n
rotations in t Second, show the angular
acceleration is given by
alpha=4pie n/t^2 rad/sec square
​

Answer 1

Answer:

Proved Below

Step-by-step explanation:

Initial angular velocity = 0

Number of rotations completed in t seconds = n

therefore, angular displacement in t seconds =2πn

from 3rd equation of motion,

displ.=1/2a*t^2

2πn=1/2at^2

a=4πn/t^2 radian per second square