Question

A constant torque of 120Nm is required to keep the shaft of engine rotating at 1000rpm.calculate the output power of the engine. ​

Answer 1

Power=torque×angular velocity

Frequency=1000/60=16.66 rps

Angular velocity=2πf

=2×3.14×16.66=104.62

Power=120×104.6

Power=12555

I hope this helps ( ╹▽╹ )