A constant torque of 20Nm produces 5 rotations on a body of mass 10 kg. The work done on the body is: /
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L₁ = initial angular momentum = 100 kgm²/s
L₂ = final angular momentum = ?
t = time interval during which the torque acts = 7 - 4 = 3 sec
τ = torque applied on wheel = 20 N-m
according to impulse -change in angular momentum equation
Torque x time interval = change in angular momentum
Using the equation
τ t = (L₂ - L₁)
inserting the values in the above equation
(20) (3) = (L₂ - 100)
60 = L₂ - 100
L₂ = 60 + 100
L₂ = 160 kgm²/s
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