Question

A constant torque of 500Nm turns a wheel about its center. the moment of inertia about this axis 100kgm.find the angular velocity gained in 4 second and kinetic energy gained after 20 revolutions​

Answer 1

Answe

10rad/s

Explanation:

Here, τ=500N−m,I=100kgm2,

(ω2−ω1)=?,t=2s

τ=Iα=I(ω2−ω1)t

(ω2−ω1)=τ×1I=500×2100=10rad/s