A constant torque of magnitude 3000Nm changes the angular velocity of a rotating body from 5 rad/s to 20 rad/s in 5 sec. Then the M.I.of the body about the axis of rotation is....
A) 1000Kgm2
B) 2000Kgm2
C) 1000 kg/m
D) 100 Kg/m2
Answers
Answered by
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Answer:
) 100 Kg/m2 this is the answer
Answered by
0
Answer:
A) 1,000 kg m^2
Step-by-step explanation:
Angular acceleration= alpha = change in angular velocity/time duration
alpha = (20-5)/5 = 3 rad/Sec^2
The formula for torque Tow = I × alpha
where I = moment of inertia
So I = tow / alpha = 3000/3 = 1000 kg m^2.
units are Nm sec^2 or kg m^2.
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