Question

(a) construct a ∆PQR, such that PQ =6cm, PR =6.5cm and < QPR =600

(b) Construct a right angled ∆ABC, in which <B =900

, BC= 6cm and AC =10cm​

Answer 1

Answer:

a)Step 1: Construct a straight line QR = 6.5 cm.

Step 2: At point Q, construct an angle of 60

o

Step 3: On the arm of this angle mark point X at a distance of 2.5 cm from Q

Step 4: Join X to R.

Step 5: Now the copy the angle formed at X on R.

Step 6: Extend the arms of both the angles and mark their intersection as P.

b)1. Draw the base BC = 6cm and at the point B make an angle 90°, say ∠XBC equal to the given angle.

2. Cut a line segment BD = 10 cm equal to AB + AC from the ray BX.

3. Join DC and make an angle ∠DCY equal to ∠BDC

4. Let CY intersect BX at A. We constructed required ∆ABC

make me as a brainliest