Question

A construction crew is building a straight ramp that rests on two beams.One beam is 3.5 feet tall and the other is 10.5 feet tall.The beams are 40 feet apart.What is the slope of the ramp?

Answer 1

Slope of ramp is

(Y1 - Y2)/(X1 - X2)

= 3.5 - 10.5 / 0 - 40

= 7/40

Hope this helps

Answer 2

The slope of the ramp is 0.175 .

Step-by-step explanation:

Since we have given that

Height of first beam = 3.5 feet = $y_1$

Height of second beam = 10.5 feet = $y_2$

Distance between the two beams = 40 feet = $x_2-x_1$

So, the slope of the ramp would be

$\dfrac{y_2-y_1}{x_2-x_1}\\\\=\dfrac{10.5-3.5}{40}\\\\=\dfrac{7}{40}\\\\=0.175$

Hence, the slope of the ramp is 0.175 .

# learn more:

A ramp into a building forms an 8° angle with the ground. If the entry point of the ramp is 7 feet from the building, how many feet from the ground is the end of the ramp? Round the solution to the nearest hundredth.

0.98 feet

1.22 feet

1.36 feet

2.01 feet

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