Science, asked by shameek5607, 10 months ago

A consumer research survey sampled 200 men and 200 women to find out whether they prefer to drink plain water or soft drink when they are really thirsty. 280 reported they prefer to drink plain water. Of the group preferring a soft drink, 80 were men and 40 were women. What is the percentage probability that a randomly chosen man will prefer a soft drink

Answers

Answered by jaiswalsindhuli717
11

Answer:p(x)=80/280=8/28

Explanation:

Answered by caffeinated
0

The percentage probability that a randomly chosen man will prefer a soft drink is 20%.

Step by step calculation

Given

The number of men under study = 200.

The number of women under study = 200.

The number of people who preferred plain water = 280.

The number of men who preferred soft drinks = 80.

The number of women who preferred soft drinks = 40.

The probability that a randomly chosen man will prefer a soft drink = ?

Probability =

= Number of men who preferred soft drink/Total number of men under study

= 40/200 = 0.2

Probability percent = 0.2 x 100 =20%

Probability for random person =

=Number of people who preferred soft drink/ Total people under study

= 80 +40/ 200+200

=120/400

= 0.3

Probablity percent = 0.3 x 100 = 30%

Probability percent that a randomly chosen man will prefer soft drink = 20%

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