Question

a consumer uses a 6 kW heater,a 4kW electric stove and three 100 watt lamps for 10 hours daily. Find the cost of electrical energy for months of June if 1 unit of energy cost Rs 3.00

Answer 1

Answer: 9270

Explanation:

1 unit of energy is 1 kwh

the total power consumption = 6+4+0.3= 10.3 ( note that 100 watt should be converted into kw)

time = 10h x 30(no. of days in June) = 300 h

so, total energy consumption = 300 x 10.3 = 3090 kwh

total cost = 3 x 3090 = Rs. 9270

Answer 2

Answer:

9270

Explanation:

1kwh =1 unit

find total energy used in a month and multiply it with rate