Question

A contact force act on an object of mass 5 kg for a duration of 2 seconds If in case the object level security metre per second to 7 metre per second find the magnitude of the applied force now is the force applied for a duration of 5 seconds what would be the final velocity of the object

Answer 1

Let the force be F.

Mass is, m = 5 kg

Time for which it is accelerated = 2 s

Velocity is increased from 3 m/s to 7 m/s

So, acceleration is, a = (7-3)/2 = 2 m/s2

The force applied is, F = ma = (5)(2) = 10 N

Now, the force is applied for 5 s, the velocity after 5 s will be,

v = u + at

=> v = 3 + (2)(5)

=> v = 13 m/s

This is the final velocity.