Question

A container "A" holds n2 gas with a mass of 84.7 g and is 2.7 times the volume of container "B" which holds argon(Ar) gas at the exact same temperature and pressure.What is the mass of the Ar(in g) in container "B"?​

Answer 1

Answer:

I HOPE THIS IS CLEAR

Explanation:

Step 1. Write the balanced chemical equation.

4NH₃(g) + 7O₂(g) → 4NO₂(g) + 6H₂O(l)

Step 2. Convert mass of NH₃ → moles of NH₃ → moles of NO₂.

100 g NH₃ × 1mol NH317.03g NH3×4mol NO24mol NH3 = 5.872 mol NH₃ (3 significant figures +

1 guard digit)

Step 3. Use the Ideal Gas Law to calculate the volume of NO₂.

PV=nRT

V=nRTP=5.872mol×8.314kPa⋅L⋅K−1mol−1×273K100kPa = 133 L