Question

A container "A" holds n2 gas with a mass of 84.7 g and is 2.7 times the volume of container "B" which holds argon(Ar) gas at the exact same temperature and pressure.What is the mass of the Ar(in g) in container "B"?Please solve it completely with numericals ​

Answer 1

Answer:

I hope this is clear

Explanation:

Step 1. Write the balanced chemical equation.

4NH₃(g) + 7O₂(g) → 4NO₂(g) + 6H₂O(l)

Step 2. Convert mass of NH₃ → moles of NH₃ → moles of NO₂.

100 g NH₃ × 1mol NH317.03g NH3×4mol NO24mol NH3 = 5.872 mol NH₃ (3 significant figures +

1 guard digit)

Step 3. Use the Ideal Gas Law to calculate the volume of NO₂.

PV=nRT

V=nRTP=5.872mol×8.314kPa⋅L⋅K−1mol−1×273K100kPa = 133 L