Question

a container contain 1120 litres of 40% solution of acid. how many litres of acid have to be added so that the resulting mixture contains more than 40% but less than 50% of water?​

Answer 1

Answer:

between 448litre and 560 litre.

Step-by-step explanation:

40% of 1120=448

50% of 1120=560

Therefore,the mixture would be between 448 and 560 litre.

Answer 2

Given:

A container contains 1120 liters of 40% solution of acid.

To Find:

Quantity of acid to be added

Solution:

The total amount of water at the initial stage = 1120 × 40/100

                                                                          = 448 litres

If the water percentage is 50% then acid is also 50% in the solution.

Let the acid added be x,

  448 + x = (1120 + x) × 50/100

⇒ x = 224 litres

If the water percentage is 40% then acid is percentage will be 60%.

Let the acid added be x litres,

     448 + x = (1120 + x) × 60/100

⇒ x = 560 litres