Question

- A container contains 10 L mixture
in which there is 10% sulphuric
acid. To make the solution to
contain 25% sulphuric acid, the
quantity of sulphuric acid to be
added in it, is​

Answer 1

Answer:2 litres

Step-by-step explanation:

Given that-

volume of the mixture is 10 litres.In which the quantity of h2so4 is 10% or 1 litre (10 × 10/100=1).

We need 25% h2so4 in the mixture.

Here suppose you mix X litre h2so4 in 10 litre mixture.

Then the quantity of h2so4= 1+X litres

and the quantity of mixture = 10+X litres.

We need 25% of h2so4

So,

1+X/10+X × 100=25

1+X/10+X=25/100

1+X10+X=1/4

Now,

4+4X=10+X

4X-X=10-4

3X=6

X=6/3

X=2

So,we should mix 2 litre h2so4.

Answer 2

Answer: add 2 litres

Step-by-step explanation: 10 +2 =12 ,3/12 ×100 =25%