Question

a container contains 16g of oxygen at 273 k if volume of the container is 11.2 litres then what is the pressure of gas

Answer 1

Answer:

pressure = 1 atm

Explanation:

from ideal gas equation

PV=nRT

no. of moles = given weight/gram molecular weight= 16/32=0.5

P×11.2= 0.5× 0.0821×273

After solving it we get pressure as 1 atm

Answer 2

Answer:

The pressure of gas is 1 atm

Explanation:

Given that,

The mass of Oxygen present=16gm

The temperature inside container=273K

Volume of Container=11.2L.

Pressure of gas=?

To find this,we use ideal gas equation i.e,

$PV=nRT$

The molar mass of oxygen is 32g/mol

Therefore,

$n = \frac{16}{32} = 0.5 \: mol$

Now substituting the known values in ideal gas equation,we get

$P(11.2) = 0.5 \times 0.0821\times 273 \\ = > P = 1 \: atm$

Therefore the pressure of gas deduced is 1atm

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