A container contains 3 red and 4 black ball. If one ball is selected at random from the container, what is the probability that it is black?
A) 3/7
B) 4/7
C) 1
D) zero
E) 3/4
F) 1/4
G) 4/3
Answers
Answered by
2
no. of black balls-4
total balls -red balls+black balls
=3+4=7
the probability of that it is black=no. of black balls\total balls
=4/7
Answered by
1
Answer:
4/7
Step-by-step explanation:
total number of ball = 4+3
=7
P ( E ) = 4/7
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