A container contains 30 liters of milk. from this container 5 liter of milk was taken out and replaced by water. this process was repeated further two times. how much milk is now contained by the container?
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1
milk in container =total quantity of milk- no. times milk taken out× quantity of milk taken out each time
=30-(3×5)
=30-15
=15liter of milk is left in container
=30-(3×5)
=30-15
=15liter of milk is left in container
Answered by
0
Answer: 17.36
Suppose a container contains x units of a liquid from which y units are taken out and replaced by water. After n operations, quantity of pure liquid
=x(1-(k/x))pow(n)
so
17.36
30(1+5/30)po
3
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