A container contains 40liters of milk from this container 4liters of milk was taken out and replaced by water. this process was repeated further two time's.how much milk is now contained by the container?
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the answer is thirty eight I guess
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Suppose a container contains "x" units of a liquid from which "y" units are taken and replaced by water. After "p" operations, quantity of pure liquid =
x ( 1 - y / x ) ^ p
milk contained by the container now
= 40 ( 1 - 4 / 40 ) ^3
= 40 ( 1 - 1 / 10 ) ^3
= 40 * 9/10 * 9/10 * 9/10
= ( 4 * 9 * 9 * 9 ) / 100
= 29.16
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