Question

a container contains 5 red and 7 black balls if one ball is selected at random from the container then what is the probability it is black​

Answer 1

Answer:

7/12

Step-by-step explanation:

total number of black balls=7

total number of balls=12

therefore, probability=7/12

Answer 2

Answer:

The answer to the given question is the probability of getting a black ball is

$\frac{7}{12}$

Step-by-step explanation:

Given :

A container contains 5 red and 7 black balls.

To find :

if one ball is selected at random from the container then what is the probability it is black

Solution :

There are 5 red and 7 black balls, and the total number of balls in the container will be 12.

Then the sample space n(S)=12

let A be the event of getting a black ball and there are

7 black balls one ball must be within these 7 balls.

Therefore, n(A) is 7.

The probability of getting a black ball is

$\frac{n(A)}{n(S)} = \frac{7}{12}$

The value obtained is 7/12

Therefore, the final answer to the given question is the probability of getting a black ball is

$\frac{7}{12}$

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