Question

A container contains 5L of nitrogen gas at 27°C.
What will be its volume if the temperature increases
to 327°C keeping pressure constant?​

Answer 1

The reaction involved, dissociation of nitrogen gas

N

2

⇌2N

mass of nitrogen =1.4g

⇒moles=1.4/28=0.05

moles after dissociation of N

2

=0.05×70/100

and after dissociation of 2N=0.05×2×30/100

total moles involved =0.065

applying ideal gas equation (PV=nRT)

P=(nRT)/V

=1.92atm

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