Math, asked by himanshusinha171995, 9 months ago

A container contains 80 litre of milk and water. The percentage of mis 31.25%. How much more milk should be add to that milk and water becomes equal.

Answers

Answered by itzJitesh
1

Answer:

Two vessels A and B contain milk and water mixed in the ratio 8:5 and ... Most Helpful Expert Reply ... say A qty of vessel A and B qty of vessel B is added together.

Answered by bhagyashreechowdhury
1

If the percentage of milk is 31.25%, then 30 litres of milk should be added so that milk and water become equal.

Step-by-step explanation:

The quantity of a initial mixture of milk and water in the container = 80 litres

The percentage of milk = 31.25%

The initial quantity of milk = 31.25% of 80 = 0.3125 * 80 = 25 litres

Let the milk to be added in the mixture be denoted as “x” litres.

So, the new quantity of milk will become = (25 + x) litres  

And,

The new quantity of mixture = (80 + x) litres

Here, we want the final quantity of milk and water in the mixture to be equal, so we can write the final equation as,

50% of [new mixture] = [quantity of milk in the new mixture]

⇒ 50% of (80+x) = 25 + x

⇒ ½ * (80+x) = 25 + x

⇒ 80 + x = 50 + 2x

⇒ 2x – x = 80 – 50

x = 30

Thus, 30 litres more milk should be added so that milk and water become equal in the new mixture.

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