Question

A container contains a mixture of two liquids a and b in the ratio 7:5. When 9 lit of mixture is drawn off and the container is filled wih



b. The ratio of a and b become 7:9 .How many lit. Of liquid a was contained by the container initially

Answer 1

Answer:

Step-by-step explanation:

Suppose the container initially contains 7x and 5x L of mixtures A and B, respectively.

Quantity of A in mixture left

= (7x−712×9)=(7x−214) L

Quantity of B in mixture left = (5x−512×9)=(5x−154)L

According to the question,

7x−214(5x−154)+9=79

28x−2120x+21=79

= 252x - 189 = 140x + 147

= 112x = 336

= x = 3

Therefore, Container contained = 7×3 = 21 L of A.

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