Question

A container filled with a sample of an ideal gas at the pressure of 1.5 atm. The gas is compressed
isothermally to one-fourth of its original volume. What is the new pressure of the gas?
​

Answer 1

Answer:

Let initial pressure, volume and temperature be P, V and T respectively.

∴ P

2

=2P

For isothermal process : P

2

V

2

=P

1

V

1

(2P)V

2

=PV ⟹V

2

=

2

V

For adiabatic process : P

2

V

2

γ

=P

3

V

3

γ

(Given γ=1.4)

⇒2P(

2

V

)

1.4

=P

3

V

1.4

⇒ 2(

2

1

)

1.4

=

P

P

3

⇒2×0.38=

P

P

3

⇒

P

P

3

=0.76

Thus, P

3

:P=0.76:1

Answer 2

hmm the answer is 3 atm

Explanation:

hi