A container has 64 g of O, at temperature T and
pressure P. If same container has 8 g of H, at
temperature 27, then its pressure will be
(2) 2P
(1) P
(3) 4P
(4) 8P
nf state corresponding to 56 g of N.
Answers
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2
The pressure will be
(3) 4P.
Given, the amount of oxygen (O) = 64 gm,
No. of moles of O (n) = Weight/Mol. Mass = 64/32 = 2
Also, the amount of hydrogen (H) = 8 gm.
No. of moles of H (n') = Weight/Mol.Mass = 8/2 = 4
The pressure of oxygen is P and the temperature of oxygen is T.
The temperature of hydrogen (T') is 2T.
Let the pressure of hydrogen be P'.
We know, P = nRT
where R is the universal gas constant.
So, P/P' = nRT/n'RT'
⇒ P/P' = (2RT)/(4R×2T)
⇒ P/P' = 1/4
⇒ P' = 4P
So, option (3) is correct.
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