Question

a container has N molecules at absolute temperature t. if the number of molecules is doubled but kinetic energy in the box remains the same as before, the absolute temperature of the gas is?

Answer 1

Hey mate,


◆ Answer-
Absolute temperature will be halved

◆ Explanation-
Let the container holds N molecules of gas at temperature T.
KE = 3/2 NRT

When, no of molecules are doubled i.e. N' = 2N,
KE' = 3/2 N'RT'
KE' = 3 NRT'

But KE' = KE, hence
3/2 NRT = 3 NRT'
T' = 1/2 T

Absolute temperature of the gas is halved on doubling no of molecules.

Hope this helps...

Answer 2

Explanation:

This is the answer.

Answer:T/2