Question

A container having 1 mole of a gas at a temperature 27 has a movable piston which maintains at constant pressure in container of 1 atm . The gas is compressed until temperature becomes 127 . The work done is ( c for gas is 7.03 cal / mol k )

Answer 1

The work done is 831 Joule.

Given-

• Moles of gas = 1 mol
• Initial temperature = 27 °C
• Pressure = 1 atm
• Final temperature = 127 °C
• Cp for the gas is = 7.03 cal/mol K

We know that at constant pressure work done is given by-

W = PΔV = nRΔT where n is the number of moles, R is the universal gas constant and ΔT is the change in temperature.

By substituting the values we get

W = 1 × 8.31 × (127-27)

W = 1 × 8.31 × 100

W = 831 Joule