Question

A Container having 1 mole of a gas at a temperature 27∘ has a movable piston which maintains at constant pressure in container of 1 atm . The gas is compressed until temperature becomes 127∘. The work done is ( C for gas is 7.03 cal / mol – K )
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Text Solution

Answer 1

Explanation:

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Asked on October 15, 2019 by

Jeeva Gandhi

At 27

o

C, one mole of an ideal gas is compressed isothermally and reversibly from a pressure of 2 atm to 10 atm.

Choose the correct option from the following:

A

Change in internal energy is positive

B

Heat is negative

C

Work done is - 965.84 cal

D

All are incorrect

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VIDEO EXPLANATION

ANSWER

Work done in isothermal reversible process is

w=−2.303nRTlog

10

p

2

p

1

Given, n=1,R=2calK

−1

mol

−1

T=(27+273)K=300K

p

1

=2atm,p

2

=10atm

∴ w=−2.303×1×2×300log

10

10

2

w=+965.54cal

For isothermal change, ΔU=0

Now, from first law of thermodynamics

q=ΔU−W=0−965.84cal

q=−965.84cal