Question

A container holds 20g of argon-40 and 40g of neon-20. what is the number of atoms of argon-40 / number of atoms of neon-20 in the container

Answer 1

The number of atoms of Argon-40 / number of atoms of Neon-20 in the container is 1/4

Explanation:

Atomic weight of Argon = 40

Mass of Argon gas in container = 20g

Moles of Argon gas in container = Mass/Atomic Weight

                                                     = 20/40 = 0.5

1 Mole will contain $=6.022\times 10^{23}$ atoms

Therefore, 0.5 mole will contain $=0.5\times 6.022\times 10^{23}$ atoms

Similarly moles of Neon in the container = mass/atomic weight

                                                                  = 40/20 = 2

1 Mole of Neon will contain $=6.022\times 10^{23}$ atoms

Therefore, 2 mole will contain $=2\times 6.022\times 10^{23}$ atoms

Now,

No. of atoms of Argon-40/No. of atoms of Neon-20

$=\frac{0.5\times 6.022\times 10^{23}}{2\times 6.022\times 10^{23}}$

$=\frac{1}{4}$

Hope this answer is helpful.

Know More:

Q: From a container having 64g oxygen ,11.2 l oxygen gas at s.t.p and 6.022 *10^23 oxygen atoms are removed. find the mass of the oxygen gas left.

Click Here: https://brainly.in/question/3731820