Question

a container holds 3 red balls, 2 orange balls, 5 yellow balls, and 3 green balls.A ball is picked at random. What is the probability of choosing neither red or green?

Answer 1

Total number of possible outcome = 3+2+5+3=13 balls
No of favourable outcomes = 13 - (3+3) =13 -6 =7
therefore probability of getting neither red nor green = 7/13

Answer 2

Total outcome =3+2+5+3
=13
Favorable outcome =3+3
=6
P(E)=Favorable /total
=6/13

Please mark this as brainliest