Question

A container holds a mixture of three nonreacting gases: n1 moles of the first gas with molar specific heat at constant volume C1, and so on. Find the molar specific heat at constant volume of the mixture, in terms of the molar specific heats and quantitites of the three separate gases.

Answer 1

Givwn,

Heat capacity C of a body as the ratio of the amount of heat energy Q transferred to a body in any process to its corresponding temperature change ΔT.

C = Q/ΔT

So, Q = C ΔT

➡Each sample will experience the equal temperature change.

If the gas has n molecules, then Q will be as ⤵⤵⤵⤵

Q = nC ΔT

Answer 2

Let the final temperature be T .

Let the initial temperature be t .

Change in temperature is represented by Δ t .

Δ = delta meaning change .

C = heat capacity of the body .

We know that C = Q / Δ t

Q is the amount of heat required to change its temperature .

Q = C Δ t

Let the number of molecules be n.

Hence amount of heat will be :

Q = C n Δt

n = number of molecules.

Δ t = change in temperature .

C = heat capacity .