A container is 12 m long, 8 m wide and 5 m high. How many cubical parcels can be accommodated in the container, if each parcel requires 8 m^3 of space?
Answers
Answer:
volume of container =lbh=12×8×5=480m^3
volume of 1 parcel =8m^3
no.of parcels accommodate=480/8=60parcels
Answer:
We can find the number of cubical parcels that can be accommodated by dividing the volume of container by the volume of cubical parcel:
No. of cubical parcels = Volume of container/Volume of cubical parcels
Volume of the container = L * B * H
= 12 * 8 * 5
= 60 * 8
= 480 m^3
Volume of cubical parcel = 8 m^3 ......................................[Given]
No. of cubical parcels = Volume of container/Volume of cubical parcels
= 480/8
= 60 boxes
Therefore, 60 cubical parcels could be accommodated in the container.