Question

A container is filled with liquid 6 part of which are water and 10 part milk

Answer 1

Let the container initially contains 16 L of liquid.

Let a L of liquid be compressing water.

Quantity of water in the new mixture = (6+6a16+a)(6+6a16+a) L

Quantity of milk in the new mixture = (10−10a16)(10−10a16) L

According to the question,

6−6a16+a=10−10a166−6a16+a=10−10a16

96 - 6a + 16a = 160 - 10a

96 + 10a = 160 - 10a

20a = 64

a = 6420=1656420=165

Therefore, Part of mixture replaced = 116×165=15116×165=15

please mark it as a brainlist please plz