Question

a container is filled with the mixture of milk and water the ratio of milk and water is same Bobby and Sammy increases the concentration to 60% .Bobby makes it by adding the milk and sunny make it by replacing the mixture with milk what is the percentage of milk added to it by Bobby to that of milk replaced by sunny

Answer 1

$\fontsize{18}{10}{\textup{\textbf{The required ratio is 5/2}}}$

Step-by-step explanation:

Bobby's Method:- Milk: Water=1:1

Target ration:-Milk:Water=6:4

Let the total quantity be 2x

therefore, (x+a)/x=6/4

                a=x/2

Sammy's Method:- Milk:Water=1:1

Again, total quantity=2x

therefore, (x-b+2b)/(x-b)  =6/4         {He took out 2b quantity of mixture, that is b quantity of milk and b quantity of water and replaced with 2b quantity of milk)

We get, b=x/5

Ratio of Bobby's to Sammy's quantity=(x/2)/(x/5)=5/2 or 250%