Question

a container is filled with the mixture of milk and water the ratio of milk and water is same Bobby and Sammy increases the concentration to 60% .Bobby makes it by adding the milk and sunny make it by replacing the mixture with milk what is the percentage of milk added to it by Bobby to that of milk replaced by sunny​

Answer 1

Percentage of milk added to it by Bobby to that of milk replaced by sunny​ =80%

Given:

A container is filled with the mixture of milk and water the ratio of milk and water is same.

Bobby and Sammy increases the concentration to 60%

Bobby makes it by adding the milk and sunny make it by replacing the mixture with milk.

To find:

What is the percentage of milk added to it by Bobby to that of milk replaced by sunny​?

Explanation:

Consider there is a 80 kg mixture is there in container.

From given data there is 40 kg milk and 40 kg water is there.

Bobby and Sammy increases the concentration to 60%

Hence bobby should add 20 kg of milk to make concentration to 60%

That is  60 kg milk and 40 kg water.

Sunny make it by replacing the mixture with milk.

So quantity of mixture will not changing that is by replacing the mixture with milk. The milk should be = 80 × $\frac{60}{100}$ = 48 kg and water must be 32 kg.

So from above information there must be Remove 16 kg of mixture because

We can remove 8 kg water and water is half in mixture.

So finally adding 16 kg of milk by sunny​.

Percentage of milk added to it by Bobby to that of milk replaced by sunny​

          = $\frac{16}{20}$ × 100 = 80%

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