A container is having 3 red balls, 2 yellow balls. If a ball is pulled out at random, then find: (a) The probability of getting a red ball. (b) The probability of getting a yellow ball.
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Answer:
P(E) for getting red balls=3/5×100=60%
p(e) for getting yellow balls=2/5×100=40%
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Given, number of red balls = 3
Number of yellow balls = 2
Total number of balls = 5
A) p( getting red balls ) = ( number of red balls )/( total number if balls)
= 3/5
B) p(getting yellow balls) = ( number of yellow balls )/( total number if balls)
= 2/5
Number of yellow balls = 2
Total number of balls = 5
A) p( getting red balls ) = ( number of red balls )/( total number if balls)
= 3/5
B) p(getting yellow balls) = ( number of yellow balls )/( total number if balls)
= 2/5
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