A container of capacity 11/2 liters takes 61/3 seconds to fill. What time will be taken by a container of capacity 35/2 liters to fill completely at the same speed?
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Answer:
Let initial quantity of mixture = x liters
Initial quality of milk = 0.75 x liters
So, 0.75x(1−x5)(1−x10)=0.54x
⇒10075x(xx−5)(xx−10)=10054x
⇒25(x2−15x+50)=18x2
⇒25x2−375x+1250=0
⇒7x2−375x+1250=0
x=2×7375±3752−4×7×1250
=14375±140625−35000
=14375+325=14700,4150
=5
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