A container of volume V, contain 0.28 gm of n2 gas .if same volume of an unknown gas under similar conditions of temprature and pressure weighs, 0.44 gm ,the molecular mass pf the gas is?
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equal volumes of gases contain equal number of molecules.
molar mass of nitrogen is 14 and N2 is 28 u. so it has 1/100 moles
The other gas also has 1/100 moles. so the molar mass should be 0.44 x 100 = 44 u.
It may be carbondioxide.
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equal volumes of gases contain equal number of molecules.
molar mass of nitrogen is 14 and N2 is 28 u. so it has 1/100 moles
The other gas also has 1/100 moles. so the molar mass should be 0.44 x 100 = 44 u.
It may be carbondioxide.
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Answered by
3
Answer:
Explanation:
Answer is 44g...........
0.28/28*0.44g
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