a container open at the top and made up of metal sheet in the form of a frustum of a cone of height 16 cm diameter of its lower and upper ends as 16cm and 40cm respectively. find the cost of metal sheet used to make the container if it cost rupees 10 per 100 cm square
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to find the cost multiply with 1760cm square
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Answer:GIVEN :
Diameter of upper end of bucket =30cm
Radius of the upper end of the frustum of cone( r1) = 15cm
Diameter of lower end of bucket = 10 cm
radius of the lower end of the frustum of cone( r2) = 5 cm
H of the frustum of Cone = 24 cm
Slant height of bucket ( L)= √(h² + (r1- r2)²
L =√24² + (15 - 5)² = √576 + 10²
L =√(576+(100)= √676 = 26cm
L = 26 cm
Area of metal sheet require to make it = π(r1 + r2)L + πr1²
= 3.14(15 + 5) × 26 + π(5)²
= 3.14 × 20 × 26 + 25 × 3.14
= 3.14 (520+ 25)
= 545 × 3.14
= 1711.3 cm²
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