Question

A Container, open at the top, is in the form of a frustum of a cone of height 24 cm with radii of its lower and upper circular end as 8 cm and 20 cm respectively. Find the cost of milk which can completely fill the container at the rate of ₹21 per litre.arpit​

Answer 1

Answer:

Cost of the milk fill in the frustum is Rs 329.2. Where h is the height , R and r is the radius of the two bases of the frustum . A container open at the top,is in the form of frustum of a cone of height 24cm with radii of its lower and circular ends as 8 cm and 20cm. Thus the volume of the frustum is 15674.88 cm³ .

Mark in bllilant

Answer 2

$According \: to \: the \: question \\ \\ </p><p></p><p>\begin{gathered}\begin{gathered}:\implies \bf{V = \dfrac{1}{3} \times \dfrac{22}{7} \times 8 \times 24 \big(20^{2} + 20 \times 8 + 8^{2}\big)} \\ \\ \\\end{gathered} \\ \\ \begin{gathered}:\implies \bf{V = \dfrac{1}{3} \times \dfrac{22}{7} \times 8 \times 24 \big(400 + 160 + 64\big)} \\ \\ \\\end{gathered} \\ \\ \begin{gathered}:\implies \bf{V = \dfrac{1}{3} \times \dfrac{22}{7} \times 8 \times 24 \big(604\big)} \\ \\ \\\end{gathered} \\ \\ \begin{gathered}:\implies \bf{V = \dfrac{1}{3} \times \dfrac{22}{7} \times 8 \times 24 \times 604} \\ \\ \\\end{gathered} \\ \\ \begin{gathered}:\implies \bf{V = \dfrac{850432}{7}} \\ \\ \\\end{gathered} \\ \\ \begin{gathered}:\implies \bf{V = 121490.3\:cm^{3}} \\ \\ \\\end{gathered}\end{gathered}</p><p>$

Let's Find the cost of milk

Cost of milk = volume of container / ₹21 per litre

Cost of milk = 121490.3 / 21

Cost of milk = 5785.25

Hence cost of Milk is ₹ 5785.25