A container open at the top is in the form of a frustum of a cone of height 24 cm with radii of its lower and upper circular ends as 8 cm and 20 cm respectively find the cost of milk which can completely fill the container at the rate of Rs 21 per litre
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h = 24cm
r = 8cm
R = 20cm
Volume = 1/3*π*h*(r^2+R^2+rR)
= 1/3*22/7*24*(64+400+160)
=22/7*8*624
=109824/7
1cm^3 = 21
109824/7 cm^3 = 21*109824/7=3*109824 =329472
r = 8cm
R = 20cm
Volume = 1/3*π*h*(r^2+R^2+rR)
= 1/3*22/7*24*(64+400+160)
=22/7*8*624
=109824/7
1cm^3 = 21
109824/7 cm^3 = 21*109824/7=3*109824 =329472
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