A container opened at the top has length 50 cm, breadth 40 cm and height 30 cm. It is made from a sheet of tin. Find the cost of tin sheet required for making 10 such containers if the cost of tin sheet is Rs 20 per square metre
Answers
Answer:
Step-by-step explanation:
dimension of cuboidal tin = 30cm×40cm×50cm
let length = 40cm
breath = 30cm
height = 50cm
Total surface area = 2(lb+bh+lh)
= 2(40×30 + 30×50 + 40×50)
= 2(1200 + 1500 + 2000)
= 2(4700)
= 9400 cm²
TSA of one tin box = 9400 cm²
TSA of 20 tin boxes = 9400×20 = 18800 cm² = 1.88m²
Cost of tin = Rs. 20/m²
Total cost = 1.88×20 =Rs. 37.60
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Dimension of the cuboidal container =50cm×40cm×30cm
Tin sheet used to manufacture the cuboid=Total surface area of the cuboid
∴ Total surface area of the cuboid=2(lb+bh+lh)
=2(50×40+40×30+30×50)=2(2000+1200+1500)=2×4700=9400m
2
∴Tin sheet used to manufacture the cuboidal container is 9400m
2
It is required to make 10 such containers.
∴ Tin sheet required to make 10 such containers=9400×10=94,000cm
3
Price of tin sheet per sq.m=Rs.20
Price of tin sheet to make 94,000cm
3
is =94,000×20=Rs.18,80,000