Question

A container, opened from the top and made up of a metal sheet, is in the form of a frustum of a cone of height 16 cm with radii of its lower and upper ends as 8 cm and 20 cm, respectively. Find the cost of the milk which can completely fill the container, at the rate of ` 20 per litre. Also find the cost of metal sheet used to make the container, if it costs ` 8 per 100 cm2. (Take p = 3.14)

Answer 1

Answer:

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Step-by-step explanation:

GIVEN -

SHAPE - CONE FRUSTUM

HEIGHT 16 CENTIMETRE

LOWER RADII = 8 CENTIMETRE

UPPER RADII - 20CM

COST OF THE MILK PER LITRE - 20RS

COST OF THE METAL SHEET PER 100 CM SQUARE - 8

FORMULA -

VOLUME -

$\frac{\pi \times h}{3} \times {r1 + r2 + r1r2}$

TOTAL SURFACE AREA

$c.s. + \pi \times {r1}^{2} + \pi \times {r2}^{2}$

NOTE - WE CAN'T FIND THE

SURFACE AREA BECAUSE TO FIND THE SURFACE AREA WE NEED THE LATERAL HEIGHT THAT IS ENGAGED WITH THE FORMULA OF CURVED SURFACE AREA OR C.S. and it is not given by you in the question.

Volume is = 10449.92 sq cm

(calculation is not shown due to being very lengthy , otherwise the solution is totally based on the formula)

cost of filling the container with milk =

(first convert the square centimetre to square metre)

= 10449.92/10000

= 1.044992 sq m.

1.04499 * 20 = 20.8998 rs

_______THANKS_______