Math, asked by vandanaagarwal15798, 1 year ago

A container originally contains 10 litres of pure spirit. From this container 1 litre of spirit is replaced with 1 litre of water. Subsequently, 1 litre of the mixture is again replaced with 1 litre and this process is repeated one more time. How much spirit is now left in the container?

Answers

Answered by FelisFelis
3

The amount of spirit left in the container is 7.29 liter.

Step-by-step explanation:

Consider the provided information.

Use the formula Q=x(1-\frac{y}{x} )^n

Where Q is the quantity, x is the originally quantity, y is the amount drawn and n is the number of times.

It is given that the originally quantity is 10 liter, 1 liter of mixture replace and the number of times we repeat the process is 3.

Substitute the respective values in the above formula.

Q=10(1-\frac{1}{10} )^3\\\\Q=10(\frac{9}{10} )^3\\\\Q=7.29

Hence, the amount of spirit left in the container is 7.29 liter.

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