Question

A container which is right circular cylinder in shape has 12cm as its diameter and 15CM height is filled with ice cream. this ice cream is to be filled into cones of height 12CM and diameter 6CM with a hemisphere shape on the top. find number of such cones that can be filled with ice cream.

Answer 1

Given:

For right circular cylinder

Diameter = 12 cm

Radius(R1) = 12/2= 6 cm & height (h1) = 15 cm

Volume of Cylindrical ice-cream container= πr1²h1= 22/7 × 6× 6× 15= 11880/7 cm³

Volume of Cylindrical ice-cream container=11880/7 cm³


For cone, 

Diameter = 6 cm

Radius(r2) =6/2 = 3 cm & height (h2) = 12 cm
Radius of hemisphere = radius of cone= 3 cm

Volume of cone full of ice-cream= volume of cone + volume of hemisphere

= ⅓ πr2²h2 + ⅔ πr2³= ⅓ π ( r2²h2 + 2r2³)

= ⅓ × 22/7 (3²× 12 + 2× 3³)

= ⅓ × 22/7 ( 9 ×12 + 2 × 27)

= 22/21 ( 108 +54)

= 22/21(162)

= (22×54)/7

= 1188/7 cm³


Let n be the number of cones full of ice cream.


Volume of Cylindrical ice-cream container =n × Volume of one cone full with ice cream

11880/7 = n × 1188/7

11880 = n × 1188

n = 11880/1188= 10

n = 10

Hence, the required Number of cones = 10

Answer 2

first convert diameter in to radius which will be 6 cm of both cylinder and 3cm of cone.

Get the volume of cylinder by formula πr²h.
then calculate volume of cone by 1/3πr²h.

Then divide the volume of cylinder by that of cone. You will get the answer