A container with volume 71.9 ml contains water vapor at a pressure of 10.4 atm and a temperature of 465 C. How many grams of the gas are in the container? plzz quick answer
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Explanation:
π =n2/v×rt
n2= πvrt
10.4×71.4×0.083lbarmol-1 k-1=n2
n2=61.63
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