Question

A container X has volume double that of container Y and both are connected by a thin tube. Du
contains same ideal gas. The temperature of X is 200K and that of Y is 400K. If mass of gas in X is m
then in Yit will be:
(A)m/8
(B)m/6
(C)m/4
(D) m/2

Answer 1

Answer:

m/2

Explanation:

x =200k=m

y=400k

y =m/2