Question

A content force acts on an object of mass 2Kg for 10 sec and increases its velocity from 5 m/s to 10 m/s . find the magnitude of applied force . if this force is applied for a duration of 15 sec , what would be the velocity of the object ?

Answer 1

m=2kg
t=10s
u=5m/s
v=10m/s
f=????

$f = m.a$
so...we need "a". acceleration

$a = \frac{v - u}{t}$
$= \frac{10 - 5}{2} = 2.5$

f=2×2.5=5N