A contract has been given to a contractor to construct the boundary of a rectangular path with perimeter 180 meter. If the length of the park is 60 meter, what is the breadth of the park? Also, find the area of the park.
Answers
Answer:
Given :
Length of the park is 60 m .
Perimeter of the path is 180 m .
To Find :
Breadth and Area of the park .
Solution :
\longmapsto\tt{Length=60\:m}⟼Length=60m
Using Formula :
\longmapsto\tt\boxed{Perimeter\:of\:Rectangle=2(l+b)}⟼
PerimeterofRectangle=2(l+b)
Putting Values :
\longmapsto\tt{180=2(60+b)}⟼180=2(60+b)
\longmapsto\tt{\cancel\dfrac{180}{2}=60+b}⟼
2
180
=60+b
\longmapsto\tt{90-60=b}⟼90−60=b
\longmapsto\tt\bf{30=b}⟼30=b
Now ,
For Area :
\longmapsto\tt{Length=60\:m}⟼Length=60m
\longmapsto\tt{Breadth=30\:m}⟼Breadth=30m
Using Formula :
\longmapsto\tt\boxed{Area\:of\:Rectangle=l\times{b}}⟼
AreaofRectangle=l×b
Putting Values :
\longmapsto\tt{60\times{30}}⟼60×30
\longmapsto\tt\bf{1800\:{m}^{2}}⟼1800m
2
So , The Area of the Rectangle is 1800 m²
Answer:
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