A contract is to be completed in 52 days and 125 men where employed each operator for 7 hr/day.after 39 days 5/7th work was completed.how many additional men would be required to complete the work on time. if each men is now operated for 8 hr/day
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Total man-hours per day = 125x7 = 875
Total man-hours in 39 days = 875x39 = 34125
Fraction of work complete = 5/7
The whole work needs = 7/5 x 34125 = 47775 man-hours
Remaining man-hours for the work to be completed = 47775-34125 = 13650
No. of days left = 52-39 = 13 days
Man-hours per day = 13650/13 = 1050
If each man works for 8hr /day, then no. of men = 1050/8 = 131.25 ≈ 132 men
No. of additional men = 132 - 125 = 7 men
7 men need to be added so as to complete the work on time.
Total man-hours in 39 days = 875x39 = 34125
Fraction of work complete = 5/7
The whole work needs = 7/5 x 34125 = 47775 man-hours
Remaining man-hours for the work to be completed = 47775-34125 = 13650
No. of days left = 52-39 = 13 days
Man-hours per day = 13650/13 = 1050
If each man works for 8hr /day, then no. of men = 1050/8 = 131.25 ≈ 132 men
No. of additional men = 132 - 125 = 7 men
7 men need to be added so as to complete the work on time.
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